A) 15 W
B) 30 W
C) 60 W
D) 120 W
Correct Answer: B
Solution :
: When bulbs are connected in series, \[P=\frac{{{P}_{1}}{{P}_{2}}}{({{P}_{1}}+{{P}_{2}})}=\frac{60\times 60}{60+60}=\frac{60\times 60}{120}=30\,W\]You need to login to perform this action.
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