A) zero
B) \[20\text{ }J{{K}^{-1}}\]
C) \[50\text{ }J{{K}^{-1}}\]
D) \[\text{360 }J{{K}^{-1}}\]
Correct Answer: B
Solution :
: Here, \[\Delta {{H}_{f}}=5.46\text{ }kJ\text{ }mo{{l}^{-1}}\] \[\Delta {{S}_{f}}=\frac{\Delta {{H}_{f}}}{T}=\frac{5.46\times 1000}{273}\text{=20}\,J{{K}^{-1}}\].You need to login to perform this action.
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