A) electron
B) hydrogen atom
C) positron
D) neutron
Correct Answer: C
Solution :
: \[_{15}^{30}P\to _{14}^{30}Si+_{a}^{b}x\] Here, \[30=30+b\Rightarrow b=0\]. \[15=14+a\Rightarrow a=1\]. \[\therefore \]Missing particle is\[_{+1}^{0}e\]. (positron)You need to login to perform this action.
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