A) 1714.3 calories
B) 1530.5 calories
C) 1050.0 calories
D) 850.8 calories
Correct Answer: A
Solution :
: Energy \[=\frac{{{V}^{2}}t}{R}J\] \[=\frac{{{(10)}^{2}}\times 3600}{50}J=\frac{100\times 3600}{50\times 4.5}cal=1714.3\,cal\].
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