AMU Medical AMU Solved Paper-1998

  • question_answer
    The velocity acquired by a particle of charge q and mass m moving through a potential difference of V volts will be

    A)  \[2qV/m\]

    B)  \[\sqrt{2qm/V}\]

    C)  \[\sqrt{m/2qV}\]

    D)  \[\sqrt{2qV/m}\]

    Correct Answer: D

    Solution :

    : Energy of the particle\[=qV\] Kinetic energy of the particle\[=\frac{1}{2}m{{v}^{2}}\] \[\therefore \]\[\frac{1}{2}m{{v}^{2}}=qV\]or\[{{v}^{2}}=\frac{2qV}{m}\]or\[v=\sqrt{\frac{2qV}{m}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner