A) 64 torr
B) 80 torr
C) 100 torr
D) 400 torr
Correct Answer: C
Solution :
: Ace. to Raoults law \[\frac{{{P}_{0}}-{{P}_{s}}}{{{P}_{0}}}=\]mole fraction of solute. \[\frac{{{P}_{0}}-80}{{{P}_{0}}}=0.2\Rightarrow {{P}_{0}}-80=0.2{{P}_{0}}\] \[\Rightarrow \]\[0.8{{P}_{0}}=80\]\[\Rightarrow \]\[{{P}_{0}}=100\,torr\].You need to login to perform this action.
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