A) 1600
B) 500
C) 350
D) 150
Correct Answer: D
Solution :
: For angular motion, \[\theta =\omega t+\frac{1}{2}\alpha {{t}^{2}}\] \[\theta =0+\frac{1}{2}\times \frac{\pi }{6}{{(60)}^{2}}rad\] \[\therefore \]\[2\pi \times \]Rotations made\[(N)=\frac{\pi \times 3600}{2\times 6}\] or Rotations made\[=N=\frac{\pi \times 3600}{2\times 6\times 2\pi }\] \[N=150\]You need to login to perform this action.
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