A) 184 N
B) 1100N
C) 1200 N
D) 1300 N
Correct Answer: A
Solution :
: Pressure of mercury on bottom\[=dgh\] \[P=13600\times 10\times \frac{12}{100}N{{m}^{-2}}\] Area of bottom\[=\pi {{R}^{2}}=3.14\times {{\left( \frac{6}{100} \right)}^{2}}{{m}^{2}}\] \[\therefore \]Force = Pressure\[\times \]area or Force\[=\frac{13600\times 10\times 12\times 3.14\times 36}{100\times 100\times 100}N\] or Force = 184.48 N.You need to login to perform this action.
You will be redirected in
3 sec