A) \[YL\alpha t\]
B) \[Y\alpha a\]
C) \[YaL\alpha t\]
D) \[Ya\alpha t\]
Correct Answer: D
Solution :
: \[Y=\frac{F}{a}\times \frac{L}{l}\]where a = area or \[F=Yal/L\] ................ (i) \[\alpha =\frac{Change\text{ }in\text{ }length\,(l)}{original\text{ }length(L)\times temperature\text{ }change(l)}\] or \[\alpha =\frac{l}{Lt}\] .................. (ii) \[\therefore \]\[F=Ya\alpha t.\]You need to login to perform this action.
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