A) 2
B) 1/4
C) 4
D) 5/2
Correct Answer: C
Solution :
: Velocity of a satellite\[v=\sqrt{\frac{GM}{r}}\] \[\therefore \]\[\frac{v_{1}^{2}}{v_{2}^{2}}=\frac{{{r}_{2}}}{{{r}_{1}}}\] or \[\frac{2mv_{1}^{2}}{2mv_{2}^{2}}=\frac{4R}{R}=\frac{K{{E}_{1}}}{K{{E}_{2}}}=\frac{4}{1}\]You need to login to perform this action.
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