A) \[Bi>Sb>As>P>N\]
B) \[Bi<Sb<As<P<N\]
C) \[N<P<Sb<Bi<As\]
D) \[Bi>Sb\tilde{\ }N\tilde{\ }P>As\]
Correct Answer: B
Solution :
: On moving down the group, the stability of \[-3\]oxidation state decreases. This is due to the following reasons (i) On descending a group the size of the atom or ion increases with the result attraction of the nucleus per newly added electron decreases (ii) A large anion connot fit easily into lattice of a small cation, (iii) As the negative charge on the ion increases, it becomes more and more susceptible to polarisation.
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