AMU Medical AMU Solved Paper-1999

  • question_answer
    Radius of gyration of uniform thin rod of length about an axis passing normally through its centre of mass is

    A)  \[\frac{L}{\sqrt{12}}\]

    B)  \[\frac{L}{12}\]

    C)  \[\sqrt{12}L\]

    D)  \[12L\]

    Correct Answer: A

    Solution :

    : For a rod, \[I=\frac{M{{L}^{2}}}{12}\] \[M{{K}^{2}}=\frac{M{{L}^{2}}}{12}\] \[K=\frac{L}{\sqrt{12}}\]


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