A) \[60287\text{ }g.mo{{l}^{-1}}\]
B) \[30242.\text{ }g.mo{{l}^{-1}}\]
C) \[40404\text{ }g.\text{ }mo{{l}^{-1}}\]
D) \[50404\text{ }g.\text{ }mo{{l}^{-1}}\]
Correct Answer: A
Solution :
: Osmotic pressure \[=\frac{n}{V}RT\] \[2.57\times {{10}^{-3}}=\frac{1.26}{M\times 200}\times 1000\times 0.0821\times 300\] \[M=60377.0\text{ }gmo{{l}^{-1}}\].You need to login to perform this action.
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