A) 100
B) 150
C) 200
D) 300
Correct Answer: A
Solution :
: Kinetic energy acquired by proton \[=(N)\times (Ve)\]in half rotation. Energy is acquired in each half turn or\[K=2NVe\]where N = Number of full rotations/turns. \[K=20\text{ }MeV=20\times {{10}^{6}}\times 1.6\times {{10}^{-19}}J\] \[\therefore \]\[N=\frac{K}{2Ve}=\frac{20\times {{10}^{6}}\times 1.6\times {{10}^{-19}}}{2\times (100\times 1000)\times 1.6\times {{10}^{-19}}}\] \[=\frac{200}{2}=100\] Number of full turns of proton between the dees = 100You need to login to perform this action.
You will be redirected in
3 sec