A) \[-0.79\]volts
B) \[-0.69\]volts
C) \[-0.59\]volts
D) \[-0.49\]volts
Correct Answer: A
Solution :
: \[{{E}_{cell}}=E_{cell}^{o}+\frac{0.0591}{n}\log [Z{{n}^{++}}]\] \[{{E}_{cell}}=-0.76+\frac{0.0591}{n}\log (0.095)\] \[=-0.76-0.030=0.79\]volts.You need to login to perform this action.
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