A) functional isomers
B) position isomers
C) chain isomers
D) stereo isomers
Correct Answer: B
Solution :
: \[\underset{A}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH}}\,\xrightarrow[{{H}_{2}}S{{O}_{4}}]{\Delta }\underset{B}{\mathop{C{{H}_{3}}CH}}\,=C{{H}_{2}}+{{H}_{2}}O\] \[\underset{B}{\mathop{C{{H}_{3}}CH}}\,=C{{H}_{2}}+HCl\xrightarrow[{}]{{}}\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C{{H}_{3}}CH}}\,=\underset{C}{\mathop{C{{H}_{3}}}}\,\] \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Cl \\ \,\,\,\,C \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}+KO{{H}_{(aq.)}}\xrightarrow[{}]{{}}\] \[\xrightarrow[{}]{{}}C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \\ \,\,\,\,D \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}+KCl.\] A and D are position isomers.You need to login to perform this action.
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