A) \[5.46\text{ }J{{K}^{-1}}\]
B) \[20\text{ }J{{K}^{-1}}\]
C) \[50\text{ }J{{K}^{-1}}\]
D) \[\text{360 }J{{K}^{-1}}\]
Correct Answer: B
Solution :
: \[\Delta S=\frac{\Delta H}{T}=\frac{5.46}{273}=0.2\,kJ\,{{K}^{-1}}mo{{l}^{-1}}\] \[=20J\,{{K}^{-1}}mo{{l}^{-1}}\].You need to login to perform this action.
You will be redirected in
3 sec