A) \[1:1\]
B) \[1:5\]
C) \[1:4\]
D) \[4:5\]
Correct Answer: B
Solution :
: Horizontal component of force\[=60\text{ }cos30{}^\circ \] \[=30N\] Acceleration of system \[a=\frac{force}{(3+12+15)}\] \[=\frac{30}{30}=1\,m/{{s}^{2}}\] \[\therefore \]\[{{T}_{2}}=\] mass pulled x acceleration \[=(3+12)\times 1=15N\] \[{{T}_{1}}=3\times 1=3N\] \[\therefore \]\[\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{3}{15}=\frac{1}{5}\]You need to login to perform this action.
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