A)
B)
C)
D)
Correct Answer: D
Solution :
The intensity of electric field (E) due to charge (q) placed at a distance (r) is given by \[E=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{r}\] In Fig. II as is evident the electric field (E) due to opposite charges cancel each other. The field due to charge at B and E are equal and opposite, hence cancel out, similarly due to A and D, and due to D and C. Therefore, resultant field is zero.You need to login to perform this action.
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