A) 0.01 K/m
B) 0.1 K/m
C) IK/m
D) 10 K/m
Correct Answer: C
Solution :
Key Idea \[\Delta {{T}_{b}}={{K}_{b}}\times m\] \[{{K}_{b}}=\frac{\Delta {{T}_{b}}}{m}\] Here, \[\Delta {{T}_{b}}={{0.1}^{o}}C\] \[m=\frac{1.8/180}{100/100}=0.1\,m\] \[{{K}_{b}}=\frac{0.1}{0.1}\] \[{{K}_{b}}=1\,\,K/m\]You need to login to perform this action.
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