A) +7
B) +5
C) +3
D) -1
Correct Answer: A
Solution :
\[HCl{{O}_{4}}\](O.N. of H) + (O.N. of Cl) + (O.N. of 0) = 0 Let oxidation number of \[Cl=x\] We know that Oxidation number of \[H=+1\] Oxidation number of \[0=-2\] Therefore, \[+1+x+4\,(-2)=0\] \[1+x-8=0\] \[x=+7\] So, the oxidation number of chlorine in \[HCl{{O}_{4}}\] is +7.You need to login to perform this action.
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