A) half
B) twice
C) \[\frac{1}{8}th\]
D) \[\frac{1}{4}th\]
Correct Answer: A
Solution :
For the equilibrium reaction : \[AB(s)A(g)+B(g)\] \[{{K}_{c}}=[A]\,\,[B]\] If the equilibrium concentration of A is doubled, then the equilibrium concentration of B would become half to maintain the constant value of \[{{K}_{c}}\].You need to login to perform this action.
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