A) \[A{{B}_{3}}\]
B) \[{{A}_{3}}B\]
C) \[A{{B}_{2}}\]
D) \[{{A}_{2}}B\]
Correct Answer: B
Solution :
Number of A atoms per unit cell \[=6\times \frac{1}{2}=3\] Number of B atoms per unit cell \[=8\times \frac{1}{8}=1\] Therefore, the molecular formula of the compound is \[{{A}_{3}}B\].You need to login to perform this action.
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