A) K
B) Cu
C) Zn
D) \[{{H}_{2}}\]
Correct Answer: A
Solution :
Key Idea The substances which have lower reduction potentials are stronger reducing agents while those which have higher reduction potentials are stronger oxidising agents. \[{{E}^{o}}_{({{K}^{+}},K)}=-2.9\,\,V\] \[{{E}^{o}}_{(Zn\,\,;\,\,Zn)}=-0.76\,\,V\] \[{{E}^{o}}_{\left( {{H}^{+}},\frac{1}{2}{{H}_{2}} \right)}=-0.0\] \[{{E}^{o}}_{(C{{u}^{2+}},Cu)}=+0.34\,V\] Here, the reduction potential of potassium is lowest. So, the potassium (K) electrode acting as strong reductant.You need to login to perform this action.
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