A) \[\text{4}.\text{6}\times \text{1}{{0}^{\text{14}}}\text{ Hz}\]
B) \[\text{2}.\text{3}\times \text{1}{{0}^{\text{14}}}\text{ Hz}\]
C) \[\text{8}.\text{2}\times \text{l}{{0}^{\text{14}}}\text{Hz}\]
D) None of these
Correct Answer: A
Solution :
From Bohrs concept, the frequency v is given by \[E=hv={{E}_{2}}-{{E}_{1}}\] \[\Rightarrow \] \[hv=B\left[ \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right]=\frac{5B}{36}\] \[\Rightarrow \] \[v=\frac{5B}{36h}\] \[=\frac{5}{36}\times \frac{2.2\times {{10}^{-18}}}{6.6\times {{10}^{-34}}}\] \[\Rightarrow \] \[v=4.6\times {{10}^{14}}Hz\].You need to login to perform this action.
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