2. Solved Papers
  3. AMU Medical

AMU Medical AMU Solved Paper-2001

  • question_answer
    A force of \[\text{1}{{\text{0}}^{\text{6}}}\text{ N}/{{\text{m}}^{\text{2}}}\]is required for breaking a material. If the density of the material is \[\text{3}\times \text{1}{{0}^{\text{3}}}\text{ kg}/{{\text{m}}^{\text{3}}},\] then what should be the length of the wire made of material, so that it breaks by its own weight?

    A)  17 m                                    

    B)  34 m

    C)  26 m                                    

    D)  23 m

    Correct Answer: B

    Solution :

                     Given,  Weight of wire = breaking stress                 \[\therefore \]  Weight = volume \[\times \] density \[\times \] g                 \[w=AL\rho g\] and        stress \[=\frac{weight\left( w \right)}{area\,\,\left( A \right)}\] \[\therefore \]  \[L\rho g={{10}^{6}}\] \[\Rightarrow \]               \[L=\frac{{{10}^{6}}}{g\rho }\] Given,   \[g=9.8\,m/{{s}^{2}},\,\,\,\rho =3\times {{10}^{3}}kg/{{m}^{3}}\] \[\therefore \]  \[L=\frac{{{10}^{6}}}{9.8\times 3\times {{10}^{3}}}=34\,m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner