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AMU Medical AMU Solved Paper-2001

  • question_answer
    When temperature is increased from \[0{}^\circ C\] to \[273{}^\circ C\], in what ratio the average kinetic energy of molecules change ?

    A)  1                                            

    B)  3

    C)  4                                            

    D)  2

    Correct Answer: D

    Solution :

                     The average kinetic energy (KE) is given by \[\therefore \]  \[KE=\frac{3}{2}kT\]where T is absolute temperature. \[\therefore \]  \[\frac{K{{E}_{1}}}{K{{E}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] Given,   \[{{T}_{1}}={{0}^{o}}C=273\,K\],                 \[{{T}_{2}}={{273}^{o}}C=546\,K\] \[\Rightarrow \]               \[\frac{{{E}_{2}}}{{{E}_{1}}}=\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{546}{273}=2\]


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