A) 3
B) 1.5
C) 1.8
D) 2
Correct Answer: B
Solution :
Average value of \[\gamma \] is taken \[\gamma =\frac{{{C}_{p}}}{{{C}_{V}}}\] For monoatomic gas : \[{{C}_{V}}=\frac{5}{2}R\], For diatomic gas \[{{C}_{V}}=\frac{5}{2}R\] Average \[{{C}_{V}}=\frac{\frac{3}{2}R+\frac{5}{2}R}{2}=2R\] From Mayers formula \[{{C}_{p}}-{{C}_{V}}=R\] \[\Rightarrow \] \[{{C}_{p}}=R+{{C}_{V}}=R+2R=3R\] \[\therefore \] \[\gamma ={{\left( \frac{{{C}_{p}}}{{{C}_{V}}} \right)}_{av}}=\frac{3R}{2R}=1.5\]
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