A) 1
B) 3
C) 4
D) 2
Correct Answer: D
Solution :
The average kinetic energy (KE) is given by \[\therefore \] \[KE=\frac{3}{2}kT\]where T is absolute temperature. \[\therefore \] \[\frac{K{{E}_{1}}}{K{{E}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] Given, \[{{T}_{1}}={{0}^{o}}C=273\,K\], \[{{T}_{2}}={{273}^{o}}C=546\,K\] \[\Rightarrow \] \[\frac{{{E}_{2}}}{{{E}_{1}}}=\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{546}{273}=2\]You need to login to perform this action.
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