A) at t = 0, \[I\]= 2 mA and with time it goes to 1mA
B) J oscillates between 1 mA and 2 mA
C) J = 2 mA at all t
D) I = 1 mA at all t
Correct Answer: A
Solution :
The current passes through the capacitor and not through the resistance which is parallel to capacitor. Thus, effective resistance is the circuit is \[{{R}_{AB}}\]. Hence, when key is pressed the current in the resistor is 2 mA. After some time the capacitor becomes fully charged and will be in steady state. Now, no current passes through the capacitor and effective resistance of the circuit will be 1000 + 1000 = 20000 \[\Omega \] \[I=\frac{V}{R}=\frac{2}{2000}\] \[1\times {{10}^{-3}}A=1\,\,m\,A\]
You need to login to perform this action.
You will be redirected in
3 sec
