A) 20 m/s
B) 33 m/s
C) 40 m/s
D) 50 m/s
Correct Answer: B
Solution :
From Dopplers effect, perceived frequency \[f\] is given by \[f=f\left( \frac{v-{{v}_{o}}}{v-{{v}_{s}}} \right)\] Given, \[\frac{f}{f}=\frac{90}{100},\,\,\,v=330\,m/s\] and \[{{v}_{s}}=0\] \[\therefore \] \[\frac{90}{100}=\frac{330-{{v}_{o}}}{330-0}\] \[\Rightarrow \] \[330-{{v}_{o}}=\frac{90}{100}\times 330=297\] \[\Rightarrow \] \[{{v}_{o}}=330-297=33\,m/s\]
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