A) \[\frac{1}{{{a}_{0}}{{v}_{0}}}\]
B) \[\frac{{{a}_{0}}^{2}}{{{v}_{0}}}\]
C) \[{{v}_{a}}{{a}_{0}}\]
D) \[\frac{{{v}_{a}}^{2}}{{{a}_{0}}}\]
Correct Answer: D
Solution :
For a body executing SHM, maximum acceleration \[({{a}_{0}})\] is given by \[{{\omega }^{2}}=A={{a}_{0}}\] ?. (i) and maximum velocity \[({{v}_{o}})\] is \[A\omega ={{v}_{0}}\] ?. (ii) where A is amplitude, co the angular velocity. Squaring Eq. (ii) and dividing by Eq. (i), we get \[A=\frac{v_{0}^{2}}{{{a}_{0}}}\]
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