A) 64.5\[\Omega \]
B) 54.5\[\Omega \]
C) zero
D) infinity
Correct Answer: A
Solution :
The impedance (Z) of a circuit is \[Z=\sqrt{{{R}^{2}}+{{X}_{C}}^{2}}\] Given, \[R=10\,\,\Omega ,\,\,\,\frac{1}{\omega C}=\frac{1}{2\pi fC}\] \[\therefore \] \[{{X}_{C}}=\frac{1}{2\times 3.14\times 50\times 50\times {{10}^{-6}}}=63.7\,\,\Omega \] \[\therefore \] \[Z=\sqrt{{{(10)}^{2}}+{{(63.7)}^{2}}}\] \[\Rightarrow \] \[Z=64.5\,\,\Omega \]
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