A) \[\frac{p}{d}\]
B) \[\sqrt{\frac{p}{d}}\]
C) \[\frac{pV}{M}\]
D) \[\sqrt{\frac{pV}{d}}\]
Correct Answer: B
Solution :
According to kinetic theory of gases \[pV=\frac{1}{3}mN{{v}^{2}}\] where, m = mass of a single molecule N = number of molecules v = root mean square velocity We know that \[m\times N=M\] \[\therefore \] \[pV=\frac{1}{3}M{{v}^{2}}\] \[v=\sqrt{\frac{3pV}{M}}\] \[\frac{M}{V}=d\] where, d is density. \[\therefore \] \[v=\sqrt{\frac{3p}{d}}\] or \[v\propto \sqrt{\frac{p}{d}}\] Rate of diffusion \[(r)\propto v\] \[\therefore \] \[r\propto \sqrt{\frac{p}{d}}\]
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