A) NaH
B) \[C{{H}_{4}}\]
C) \[Ca{{H}_{2}}\]
D) \[{{B}_{2}}{{H}_{6}}\]
Correct Answer: D
Solution :
Key Idea According to Lewis ?acid is a species that can accept an electron pair to form a coordinate covalent bond.? Thus, an acid is an electron pair acceptor. It is an electron deficient species. \[{{B}_{2}}{{H}_{6}}\] is electron deficient molecule. It acts as Lewis acids and can accept electron pairs. These hydrides form adducts with ammonia and other Lewis bases. \[{{B}_{2}}{{H}_{6}}+2M{{e}_{3}}N\xrightarrow{{}}2[M{{e}_{3}}N\,.\,B{{H}_{3}}]\] \[{{B}_{2}}{{H}_{6}}+2N{{H}_{3}}\xrightarrow{Excess\,\,N{{H}_{3}}}{{B}_{2}}{{H}_{6}}.\,\,2N{{H}_{3}}\] \[{{B}_{2}}{{H}_{6}}+2{{(C{{H}_{3}})}_{2}}O\xrightarrow{{}}2[{{(C{{H}_{3}})}_{2}}O\to B{{H}_{3}}]\] \[{{B}_{2}}{{H}_{6}}+2{{(C{{H}_{3}})}_{2}}S\xrightarrow{{}}2[{{(C{{H}_{3}})}_{2}}S\to B{{H}_{3}}]\]
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