A) \[\text{2}.\text{3}\times \text{1}{{0}^{-\text{8}}}\text{ N}\]
B) \[\text{4}.\text{6}\times \text{1}{{0}^{-\text{8}}}\text{ N}\]
C) \[\text{1}.\text{15}\times \text{1}{{0}^{-8}}\text{ N}\]
D) None of these
Correct Answer: A
Solution :
From Coulombs law, the force between the two charges \[({{q}_{1}},{{q}_{2}})\] separated by distance r is \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] Given, \[{{q}_{1}}={{q}_{2}}=1.6\times {{10}^{-19}}\], \[r=1\,\overset{o}{\mathop{A}}\,={{10}^{-10}}m\] \[\therefore \] \[F=9\times {{10}^{9}}\times \frac{{{(1.6\times {{10}^{-19}})}^{2}}}{{{({{10}^{-10}})}^{2}}}\] From Snells law \[_{1}{{\mu }_{2}}=\frac{\sin i}{\sin r}\] ?. (i) Where \[_{1}{{\mu }_{2}}=\frac{{{\mu }_{2}}}{{{\mu }_{1}}}\] .? (ii)
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