A) \[C{{H}_{3}}Cl\]
B) \[C{{H}_{2}}C{{l}_{2}}\]
C) \[CHC{{l}_{3}}\]
D) \[CC{{l}_{4}}\]
Correct Answer: C
Solution :
When acetone is treated with bleaching powder, then chloroform is formed, Bleaching powder \[(CaOC{{l}_{2}})\] supplies the necessary chlorine and slaked lime (calcium hydroxide) for the reaction. \[\underset{\begin{smallmatrix} bleaching \\ powder \end{smallmatrix}}{\mathop{CaOC{{l}_{2}}}}\,+{{H}_{2}}O\xrightarrow{{}}\underset{\begin{smallmatrix} slaked \\ \lim e \end{smallmatrix}}{\mathop{Ca{{(OH)}_{2}}}}\,+C{{l}_{2}}\] Chlorine so obtained acts as a chlorinating agent. It reacts with acetone and gives trichloroacetone which formed chloroform on hydrolysis. \[\underset{acetone}{\mathop{C{{H}_{3}}COC{{H}_{3}}}}\,+3C{{l}_{2}}\xrightarrow{{}}\underset{trichloroacetone}{\mathop{C\,.\,\,C{{l}_{3}}\,.\,COC{{H}_{3}}}}\,\] \[+3HCl\] \[Ca{{(OH)}_{2}}+2CC{{l}_{3}}COC{{H}_{3}}\xrightarrow{{}}\underset{chloroform}{\mathop{2CHC{{l}_{3}}}}\,\] \[+{{(C{{H}_{3}}COO)}_{2}}Ca\] calcium acetate This is the laboratory method of chloroform preparation. Note - Ethyl alcohol also gives chloroform with bleaching ponder. In this reaction bleaching powder functions as oxidising, chtorinating and hydrolysing agent.
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