A) 1.125 N-m
B) 5.25 N-m
C) 6.25 N-m
D) 10 N-m
Correct Answer: A
Solution :
The torque acting is given by \[\tau =NI\,AB\,\sin \theta \] Given, N = 100, \[I=1\,A\], A = 15 cm \[\times \] 15 cm \[=225\times {{10}^{-4}}{{m}^{2}}\], \[B=0.5\,Wb/{{m}^{2}}\], \[\theta ={{90}^{o}}\]. = 1.125 N-mYou need to login to perform this action.
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