A) 17 m
B) 34 m
C) 26 m
D) 23 m
Correct Answer: B
Solution :
Given, Weight of wire = breaking stress \[\therefore \] Weight = volume \[\times \] density \[\times \] g \[w=AL\rho g\] and stress \[=\frac{weight\left( w \right)}{area\,\,\left( A \right)}\] \[\therefore \] \[L\rho g={{10}^{6}}\] \[\Rightarrow \] \[L=\frac{{{10}^{6}}}{g\rho }\] Given, \[g=9.8\,m/{{s}^{2}},\,\,\,\rho =3\times {{10}^{3}}kg/{{m}^{3}}\] \[\therefore \] \[L=\frac{{{10}^{6}}}{9.8\times 3\times {{10}^{3}}}=34\,m\]You need to login to perform this action.
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