A) 3.0 atm
B) 2.0 atm
C) 1.0 atm
D) 1.5 atm
Correct Answer: A
Solution :
Pressure \[p=\frac{1}{3}\rho {{c}^{2}}\] Given, \[\rho =8.99\times {{10}^{-2}}kg/{{m}^{3}}\], c = 3180 m/s \[\therefore \] \[p=\frac{1}{3}\times \frac{8.99\times {{10}^{-2}}\times {{(3180)}^{2}}}{1.01\times {{10}^{5}}}\] \[\Rightarrow \] p = 3 atmYou need to login to perform this action.
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