A) \[\Delta H>\Delta E\]
B) \[\Delta H<\Delta E\]
C) \[\Delta H=\Delta E\]
D) \[\Delta H\] is independent of physical state of reactants
Correct Answer: B
Solution :
Key Idea The relation between \[\Delta H\] and \[\Delta E\] is given by \[\Delta H=\Delta E+\Delta {{n}_{g}}RT\] where \[\Delta {{n}_{g}}=\Sigma \] product of gaseous mole \[-\Sigma \]readout of gaseous mole For the reaction \[CO(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}C{{O}_{2}}(g)\] \[\Delta {{n}_{g}}=(1\,mol\,of\,C{{O}_{2}})\] \[-(1\,\,mol\,of\,CO+0.5\,\,mol\,of\,{{O}_{2}})\] \[\Delta {{n}_{g}}=-0.5\], ie, it is negative. Hence, \[\Delta H<\Delta E\] Note - If \[\Delta {{n}_{g}}=0\], \[\Delta H=\Delta E\] \[\Delta {{n}_{g}}=+ve\] \[\Delta H>\Delta E\]
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