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AMU Medical AMU Solved Paper-2001

  • question_answer
    To deposit 0.634 g of copper by electrolysis of aqueous cupric sulphate solution, the amount of electricity required (in coulombs) is

    A)  1930                                     

    B)  3960

    C)  4825                                     

    D)  9650

    Correct Answer: A

    Solution :

                     Key Idea The quantity of electricity which can be deposited or liberated weight equal to equivalent weight is called one faraday.                 1 faraday = 96500 C Atomic weight of copper = 63.4 Equivalent weight of copper \[=\frac{63.4}{2}=31.7\] \[\because \,31.7\,g\] of copper is deposited by                                                 = 96500C \[\therefore \] 1 g of copper is deposited by \[=\frac{96500}{31.7}C\] \[\therefore \] 0.634 g of copper is deposited by                 \[=\frac{96500}{31.7}\times 0.634=1930\,\,C\]


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