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AMU Medical AMU Solved Paper-2001

  • question_answer
    The oxidation state of Ni in Ni \[{{(CO)}_{4}}\]is

    A)  zero                                     

    B)  -2

    C)  +2                                         

    D)  +4

    Correct Answer: A

    Solution :

                     Let the oxidation number of Ni is x in \[Ni{{(CO)}_{4}}\]. So,          \[x+4\,(0)=0\]                 \[x=0\] Note - Oxidation number of a metal in carbonyl complex is always zero.


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