A) -5.40 eV
B) -0.54 eV
C) -2.72 eV
D) -0.85 eV
Correct Answer: B
Solution :
Key Idea The Bohrs energy of an electron is given by \[{{E}_{n}}=\frac{13.6\,{{Z}^{2}}}{{{n}^{2}}}eV\] Z = atomic number n = number of orbit = 1, 2, 3... \[\infty \] Here, n = 5, Z = 1 \[{{E}_{5th}}=-\frac{13.6\times {{1}^{2}}}{{{(5)}^{2}}}eV\] \[=-\frac{13.6}{25}=-0.544\,\,eV\]You need to login to perform this action.
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