A) 0.2 A
B) 0.8 A
C) 1.5 A
D) 2.4 A
Correct Answer: B
Solution :
The given circuit consists of three resistors \[{{R}_{2}},{{R}_{3}}\] and \[{{R}_{4}}\] in series while \[{{R}_{1}}\] is connected in parallel to their equivalent. \[\therefore \] \[R={{R}_{2}}+{{R}_{3}}+{{R}_{4}}\] \[=5\,\Omega +5\,\Omega +5\,\Omega =15\,\Omega \] \[\therefore \] \[\frac{1}{R}=\frac{1}{R}+\frac{1}{{{R}_{1}}}=\frac{1}{15}+\frac{1}{5}\] \[\Rightarrow \] \[R=3.75\,\Omega \] \[I=\frac{V}{R}=\frac{3}{3.75}=0.8\,A\]You need to login to perform this action.
You will be redirected in
3 sec