A) zero
B) -2
C) +2
D) +4
Correct Answer: A
Solution :
Let the oxidation number of Ni is x in \[Ni{{(CO)}_{4}}\]. So, \[x+4\,(0)=0\] \[x=0\] Note - Oxidation number of a metal in carbonyl complex is always zero.You need to login to perform this action.
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