A) 800
B) 1600
C) 1200
D) 900
Correct Answer: B
Solution :
Efficiency of Carnot engine \[(\eta )\] is given by \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{W}{Q}\] Given, \[{{T}_{2}}=300K,\,\,{{T}_{1}}=600\,K,\,\,W=800\,J\] \[\therefore \] \[1-\frac{300}{600}=\frac{800}{Q}\] \[\Rightarrow \] \[Q=\frac{800}{0.5}=1600\]J/cycleYou need to login to perform this action.
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