A) \[\sqrt{2}T\]
B) \[\frac{T}{\sqrt{2}}\]
C) \[\frac{T}{\sqrt{3}}\]
D) \[\sqrt{3}T\]
Correct Answer: B
Solution :
The period of oscillation of a body of mass m suspended by a spring is\[T=2\pi \sqrt{\frac{m}{k}}\] On cutting the spring into two equal parts, the length of each part will remain half and the force constant of each part will be doubled (2k). Hence, new time period is \[T=2\pi \sqrt{\frac{m}{2k}}=\frac{T}{\sqrt{2}}\]You need to login to perform this action.
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