A) 0.1 M NaCI
B) 0.1 M urea
C) 0.1 M \[BaC{{l}_{2}}\]
D) 0.1 M glucose
Correct Answer: C
Solution :
Key Idea \[\Delta {{T}_{b}}={{T}_{2}}-{{T}_{1}}\] where, \[{{T}_{2}}\] is boiling temperature of solution\[{{T}_{1}}\] is boiling temperature of solvent. \[\Delta {{T}_{b}}=i\times {{K}_{b}}\times \] molality Here, molality of all solution is same. So, \[\Delta {{T}_{b}}\propto i\] where, i = vant Hoff factor \[i=[1+(y-1)x]\] where, y = number of products (ion or molecule) \[i=[1+(y-1)x]\] Here, \[x=1\]Solute | lonisation | y | Assume complete ionisation |
NaCI | \[N{{a}^{+}}+C{{l}^{-}}\] | 2 | 2 |
Urea | No ionisation take place (non-electrolyte) | 1 | 1 |
\[BaC{{l}_{2}}\] | \[B{{a}^{2+}}+2C{{l}^{-}}\] | 3 | 3 |
Glucose | No ionisation takes place(non-electrolyte) | 1 | 1 |
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