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AMU Medical AMU Solved Paper-2002

  • question_answer
    One end of a uniform rope of length L and of weight w is attached rigidly to a point in the roof and a weight \[{{w}_{1}}\]is suspended from its lower end. Ifs is the area of cross-section of the \[\frac{3L}{4}\] wire, the stress in the wire at a height  from 4 its lower end is

    A)  \[\frac{{{w}_{1}}}{s}\]                                  

    B)  \[\frac{{{w}_{1}}+\frac{w}{4}}{s}\]

    C)  \[\frac{{{w}_{1}}+\frac{3w}{4}}{s}\]                      

    D)  \[\frac{{{w}_{1}}+w}{s}\]

    Correct Answer: C

    Solution :

                     Stress on rope \[=\frac{force}{area}\] Stress in the rope will be due to the downward weight. \[\therefore \] Weight of \[\frac{3}{4}th\] of rope \[=\frac{3}{4}w\] Tension in rope \[={{w}_{1}}+\frac{3}{4}w\] \[\therefore \]              Stress \[=\frac{{{w}_{1}}+\frac{3}{4}w}{s}\]


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